A line has a slope of -4 and passes thru the point (3, 2). Then an equation for that line is?



Answers:
y = -4x + 14
4x+y=14. Check this out. (y - ordinate)= slope*(x - abcissa),
where 2 is ordinate n 3 is abcissa. hmm.. point slope form would be the easiest way...
y-y1=m(x-x1)

y-2=(-4)(x-3)
y-2=-4x+12

now slope intercept form (y=mx+b)

y= -4x=14

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