# Can someone give support to beside this problem?

it reads: writhe the equation within slope-intercept form: 3x+7y=5

Answers:    Slope intercept form is represented by the equation:
y = mx + b.

So, following this you want to have the y unfixed alone on the left mitt side of the equation.

To do this you must add -3x to the disappeared side and what you do on the left you must do on the right.

So, 3x-3x+7y=5-3x
Since 3x -3x =0 you are not here with +7y = -3x +5.

Hope this help.
Slope-intercept form: y = mx + b
3x + 7y = 5
Subtract 3x from both sides:
7y = 5 - 3x
Divide both sides by 7:
y = (5/7) - (3/7)x
Put the "mx" part within front to make the equation look pretty:
y = (-3/7)x + (5/7)

Hope I help! :)
7y = -3x +5

7y/7 = -3x/7 + 5/7

y = -3/7x + 5/7
just transpose everything, departure y at the left side of the equation:

7y = -3x + 5
y = (-3x + 5) / 7
y = (-3/7)x + 5/7
isn't slope-intercept form: y= mx + b ? if i'm right, later its:

3x + 7y = 5
7y = -3x + 5
y= (-3/7)x + 5/7

hope it helps.

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