A: L(-7, 0), Y(5,9)
B: U(1,3), B(4,6)
Find the coordinates of the missing endpoint of a segment having the given endpoints.
C: K (-9,3), H (5,7)
D: W (-12,-7), T (-8,-4)
Find the coordinates of the missing endpoint given that E is the midpoint of line DF.
1. F(5,8), E(4,3)
2. F(2,9), E(-1,6)
3. D(-3, -8). E (1,-2)
Answers:
Part 1:
The distance formula is sqrt[(x2 -x1)^2 + (y2-y1)^2]
1) (-7,0), (5,9)
d = sqrt[(5 - -7)^2 +(9-0)^2]
d = sqrt[(12^2 +9^2]
d = sqrt(144+81)
d = sqrt(225)
d = 15
Part 2: I assume you are looking for the midpoint.
The midpoint of two points (x1,y1) and (x2,y2) is
((x1+x2)/2, (y1+y2)/2)
1) The midpoint of (-9,3) and (5,7) is
((-9+5)/2, (3+7)/2)
= (-4/2, 10/2)
= (-2,5)
Part 3: To find the endpoint, you're going to use the same formula from above.
Assume the missing endpoint is (x,y)
The given endpoint is (5,8), and the midpoint is (4,3)
Therefore,
(x+5)/2 = 4 and (y+8)/2 = 3
Solving the first one, you get x = 3, and the second one gives you y = -2.
Now you have all the information you need to do the other problems.
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