**Question:**Ix^2+4x+4I

**Answers:**

Find out where it equals zero.

x^2 +4x +4 = 0

Factor

(x+2)^2 = 0

x+2 = 0

x = -2

This is where you would normally divide it up, but this is a special case.

Since (x+2)^2 is never negative, you don't actually need the absolute value bars.

|x^2 +4x +4| = x^2 +4x +4

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