Answers:
(n - 5)^2 = 20
Expand the left side:
(n - 5)(n - 5) = 20
n^2 - 10n + 25 = 20
Now, set the equation equal to zero:
n^2 - 10n + 25 = 20
n^2 - 10n + 5 = 0
To solve for n, you'll have to use the quadratic formula:
n^2 - 10n + 5 = 0
[-b ± sqrt(b^2 - 4ac)] / 2a
Where a = 1, b = -10, c = 5
n = 5 - 2*sqrt(5) = 0.527864
n = 5 + 2*sqrt(5) = 9.47214
Good luck in your studies,
~ Mitch ~
P.S. - Ichweissallez's answer is the easiest to understand.
Put everything in the square route.
and once done, it should look like
When you put something in a sqrt you must make it [+/-]
(n-5)=[+/-]sqrt20
SIMPLIFY THE ROUTE
(n-5)=[+/-]2sqrt5
ADD 5 TO BOTH SIDES
n=5[+/-]2sqrt5**
**edit when i did my last step I didn't copy correctly
people below me can't leave 20 in a sqrt because it's not simplified (2sqrt5 is more acceptable than sqrt20)
Here's how to start...
(n-5)(n-5) = 20
Use FOIL (first, outside, inside, last)
Solve for N
the guy's answer after mine makes a LOT more sense -- taking the square root of each side
You can take the square root of both sides of the equation, getting N-5 = +/- sqrt(20). Now you can add 5 to each side, getting N = 5 + sqrt(20) or N = 5 - sqrt(20). And that's all there is to it; numerical values, if needed, could be obtained with a calculator.
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