Answers:
They don't intersect. The first equation is for a circle centered at (0,0): the second is a line w/ y-int of 10, and an x-int of -10.
They NEVER touch.
by the way, the answer CANNOT be (3,1) as the person above me has stated: Just try plugging it into both equations:
x^2+y^2=16
3^2+1^2=16
9+1=16
10=16
Um, no way
Even the 2nd one:
y=x+10
3=1+10
3=11
umm, no!
The reason its wrong is because sqrt(x^2+y^2=16) does not equal x+y=4... that is JUST WRONG. it cannot be done that way. No offense :)
x^2+y^2=16 is equal to x+y=4 (Spaure root the hole thing) plug in the second equation into thisone x+(x+10)=16 x+x+10=16 2x=6 6/2=3=x x=3 now plug the three into one ther equation 3+y=4 (subtract 3 from both sides) y=1 the answer is (3,1)
This article contents is post by this website user, EduQnA.com doesn't promise its accuracy.
More Questions & Answers...