How do you solve (x^3-8)/(x-2)?

Question:

Answers:
Factor x^3 -8 into (x-2)(x^2 +2x +4) by using the difference of cubes formula.
Then cancel the (x-2)'s leaving you with x^2 +2x + 4.
x^3-8/x-2

(x-2)(x^2+2x+4)/x-2

x^2+2x+4

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