How would i solve this algebraic equation?

Question:Need to solve for x.

sqrt(x)=³sqrt(x)

its a three after the equal sign.

Answers:
e=mc2 lol
do you mean the cube root of x?

If so, 0 and 1 can be solutions of this one...

the square root of 0 equals the cube root of 0 - both equal 0
and
the square root of 1 equals the cube root of 1 - both equal 1
Is the question:
sqrt(x) = 3 sqrt(x)
or
sqrt(x) = cbrt(x) where 'cbrt' denotes 'cube root'?

In the first case, square the equation.
x = 9x
9x - x = 0
8x = 0
x = 0.
When you square an equation you must always check the results, as squaring can introduce extra solutions which may not be valid. x = 0 is all right.

sqrt(x) = cbrt(x)
Raise each side to the 6th power:
x^3 = x^2
x^3 - x^2 = 0
x^2(x - 1) = 0
x = 0 or x = 1.
Both roots check out.
sqrt(x) = cbrt(x)
Raising each side to the 6th power we shall get
x^3 = x^2
x^3 - x^2 = 0
x^2(x - 1) = 0
x = 0 or x = 1.

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