K(x^2)-3x+2=0 Find all values of k and x has two real solutions... PLEASE HELP!?

Question:I really need help on my Pre-Cal College course! So all you math wizzards out there please help me out!

Answers:
k(x^2)-3x+2=0

When the discriminant of the quadratic formula is greater than zero, then you will have two real roots.
The discriminant is b^2 -4ac
From the above equation, a = k, b = -3, and c = 2.
Plugging in you get
(-3)^2 - 4(k)(2)
= 9 - 8k

Set this to be greater than zero and solve for k.
9 - 8k > 0
Add 8k to both sides
9 > 8k
Divide both sides by 8
9/8 > k
Flip
k < 9/8
x1=-2
x2=-1
You COULD do your own homework. You could even put the formula into Excel or Lotus.
You might even draw a parabola.
if x =2 then the promblem is 3+2 that =5 and so u do 5+2=7 k=2 and x=2 only if x=2 or x1=2 and x2=1
you gotta figure it out yourswlf

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