2) 5 - 1(2x + 3) = -2(4 + x)
Can anybody tell me how to do these please?
Thanks!
Answers:
1) First, you use the distributive property on both sides to get rid of the parentheses. ((-2*6)-(-2*-2x))= ((4*-3)+4*x))
You get -12-4x=-12+4x. Then, you add 12 to each side to cancel the 12s. You get -4x=4x. So, you add 4x to each side to get 0=8x. Finally, you divide by 8 to get that x=0.
2) Again, you use the distributive property on both sides to get 5+2x-3=-8-2x. Then, you simplify to get 2+2x=-8-2x. After that, you subtract 2 and add 2x to get 4x=-10. Finally, you divide by 4 to get x=-2.5. sorry for all the words!
1)
-2(6-2x)=4(-3+x)
-12+4x= -12+4x
Answer- all real numbers
2)
5-1(2x+3)= -2(4+x)
5-2x-3=-8-2x
2-2x= -8-2x
10-2x= -2x
Answer- no solution
You need to distribute (multiply the numbers outside the parenthesis by each of the numbers inside them)
1) -2(6) - (-2)(2x) = 4(-3) + 4(x)
-12 + 4x = -12 + 4x
Notice that we have the exact same equation on each side of the equals sign. When this happens, the answer is "All real numbers".
2) 5 +(-1)(2x) + (-1)(3) = -2(4) + (-2)(x)
5 - 2x - 3 = - 8 - 2x
2 - 2x = -8 - 2x Adding 2x to both sides gives:
2 = -8
Since 2 does not in fact equal -8, the answer is " No Solution".
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