problem 1:
An internet service provider charges 9.95/month for the first 20 hours and then 50 cents for each additional hours. write an expression representing the charges for "h" hours use in one month when h is more than 20 hours. What is the charge for 35 hours?
i dont get what this question is asking, please help?!
Answers:
When h>20...
.50(h-20) + $9.95
.50(35-20) + $9.95
.50(15) + $9.95
7.50 + $9.95
$17.45
FYI, when h<20...
the charge will be $9.95 regardless
charge=9.95+ h*50
(50/100) =.5
charge for 35 hrs
charge=9.95+35*.5 = 27.45
what u have is that the charge of the first 20 hours is constant and any hours more u're charged 50 cents each now if u wanted to get the charge in one month when the hours are more 20 hours u have to add the constant 20 hours charge and theextra hours "H" multiplied by 50 cents or $0.5
you have more than 20 hours so first you pay 9.95 plus 50 cents for each additional hour (H) Y is the amount you pay.
9.95 + .50(H) = y
so.. you have 35 hours
first do 35 - 20 to get the number of additional hours which is 15.
so you pay 9.95 for first 20 hours then 50 cents for each of the 15 hours left
9.95+ .50 (H)=y plug in 15 for H
9.95 + .50 (15) = y
Y= $17 45 your answer. its an easy question once you understand.
BTW user coolj is wrong as you can see.
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