At noon a train leaves bridgton heading east at 90 mi/h to cogsville, 450 miles away. at 12:15 a train ..?

Question:leaves cogsville heading west to bridgton at 100 mi/p. at what time will they pass each other?

my teacher tells us to make a chart like this:


east train (rate)90 (time) x =(distance) 90x
west train (rate)100 (time) x- (1/4) =(distance) 100[ x - (1/4)]

i just need help setting up the equation dont solve plz!
and if you could explain why you set it up the way you did that would be helpful too.


thanks

Answers:
At time x hours after noon, the first train is 90x miles from Bridgton.
At the same time, the second train is 100(x - (1/4)) miles from Cogsville.
When the trains meet, the sum of these two distances is 450 miles (the distance from Cogsville to Bridgton).
Therefore your equation is:
90x + 100(x - (1/4)) = 450.

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You've almost solved the problem.

When the trains pass each other, the total distance covered by them euals the distance between Cogsville and Bridgton:

90x+100(x-1/4)=450

By the way, the answer is
x = 2.5 hours

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