How do I find the original dimentions of a rectangle, given the following:?

Question:The length is 3 times the width. The length and width are both reduced by 2. The area of the rectangle is reduced by 36. This is exactly as appears in my book, any help would be greatly appreciated.

Answers:
Length= 3*width
Length=l
Width = w
(l-2)(w-2)=lw-36 (because lw is the area)
plug in 3w for l
(3w-2)(w-2)=3w^2-36
3w^2-8w+4=3w^2-36
-8w=-40
w=5
l=15

and to check plug back in
the area of the original is 5*15=75
The area of the adjusted is 3*13=39
75-39=36
PERFECT!!

PS... chase is an idiot!
3L=W
therefore because 3L + W= 36 and 3L= W, then its safe to say that 2W= 36.
Then one W=18
Then 3L=18 so 18 divided by 3.L=6
This means that the orig. because the new one is reduced by 2
Orig L=8
Orig W=20
Orig area= 160
Also L is length and W is width..sorry if confusion

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