# There are 850 douglas fir and ponderosa pine trees in a section of forest bought by sawz loggin co.?

Question:the company paid an average of \$300 for each douglas fir and \$225 for each ponderosa pine. If the conpany paid 217,500 for the trees, how many of each kind did the company buy?

Hi,
I am looking for help setting this problem up please. Thanks

Lets represent x as the number of firs and y as the number of pines.

The sum of both is 850 ==> x + y = 850

The total price of each type is determined by the price of the type of tree multiplied by the number of trees, add them up and you'll get 217500.

==> 300x + 225y = 217500

these are your two equations needed to solve the problem.

You can solve the first equation in terms of x ==> x=850-y

Now substitute this equation into the second equation.

300(850-y) + 225y = 217500

==> 255000-300y + 225y = 217500

==> 255000 - 75y = 217500

==> -75y = -37500

==> y = 500

Now take this answer to the first equation
==> x + 500 = 850

==> x = 350

Therefore:
The number of firs is 350 and the number of pines is 500.
They should be fined by the EPA for sawing without a license,
350 douglas and 500 ponderosa

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