# Can someone simplify (4+5i)/(1-3i)?

Question:and express the answer in a+bi form?

Answers:
You need to multiply the numerator and denominator by the conjugate of the denominator, which is (1 + 3i).
This will give you (4 +12i + 5i + 15i^2)/(1 +3i - 3i -9i^2).
Now combine like terms and remember that i^2 = -1, so we have
(4 + 17i - 15)/(1 + 9)
Simplify again
(-11 + 17i)/10
If it has to be in a + bi form, you might separate the terms to
-1.1 +1.7i
try 4+5i/1-3i * 1+3i/1+3i

let me know what you get. Its called multiplying buy the conjugate
(4+5i)(1-3i)
=4-12i+5i-15i^2
=4-7i+15(-1) , i^2=-1 if i is a complex number
=-11-7i

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