How do you remove the modulus sign for the following problem?: |-3t+51|=?

Question:

Answers:
|-3t+51|

if -3t+51>0, then |-3t+51|= -3t+51
if -3t+51<0, consequently |-3t+51|= -(-3t+51)

I think surrounded by this case, the modulus sign funds magnitude. The size, |a+b| = (a^2 + b^2)^(1/2). Therefore, the magnitude of that expression is (9t^2 +2601)^(1/2). Of course, the modulus sign could also miserable the positive (absolute) value of that expression, and that number depends on the good point of t. You solve the equation for both positive and negative results.

-3t + 51 = s
-3t + 51 = -s

How do you remove the modulus sign for the following problem?: |-3t+51|=?

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