Find the slope of a line parallel to the graph of the wquation.
1. y=1/2x + 2.3
4. 3x + 4y= 12
5. 7x - y = 5
For the slope ignore the constants. For any equation y = ax + b the slope is a; b is not relevant.
1. y=1/2x + 2.3; a=1/2; therefore slope is 1/2
2. y=x; a = 1; therefore slope is 1
3. y=6; rewrite as y= 0x + 6; a = 0; therefore, slope is 0
4. 3x + 4y= 12; rewrite as y = -3/4x - 3
a= -3/4; therefore slope = -3/4
5. 7x - y = 5; rewrite as y = 7x -5
a=7; therefore, slope = 7
The slope of a line measures the steepness of the line.
Most of you are probably familiar with associating slope with "rise over run".
Rise means how many units you move up or down from point to point. On the graph that would be a change in the y values.
Run means how far left or right you move from point to point. On the graph, that would mean a change of x values.
no homework, its summer
always remember y=mx +b
m is slope and b is y-intercept.
set the equations equal to Y
to find a parallel line, keep the same slope, just a different y-intercept. (there is no wrong answer for this.)
First: find the slope of the equation
you have to make the equation into this: y = mx + c
Where: m = slope; c = intercept
second: suppose slope of a line parallel = n
m.n = -1
1. m = ½
n = (-1)/(1/2) = -2
2. m = 1
n = (-1)/1 = -1
3. m = 0
n = unlimited
4. 3x + 4y = 12
4y = -3x + 12
y = -3/4x + 3
m = -3/4
n = (-1)/(-3/4) = 4/3
5. 7x – y = 5
-y = -7x +5
y = 7x – 5
m = 7
n = (-1)/7 = -1/7
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