1.Every Sat afternoon, Mrs Gray go to work and leaves her KIDS w/MRs White whose daughter is younger than Mrs Gray's KIDS 2.Tina is older than Larry and younger than the Green's Child 3.The BRown Girl is two years elder than Lisa 4.Rita's mom who is sometimes home on Saturday afternoons occasionally takes fastidiousness of Gary while his mom goes shopping for the afternoon.
So that is to say
Kids Names: Gary Larry Lisa Rita Tina
Last Names: Brown Gray Green White
Ages,one for each child no doubles,220.127.116.11.7
All my philosophy have be wrong. Please help or if you know of a site that could minister to? :(
Answers: Okay. We know that Mrs. Gray works EVERY SAT AFTERNOON, so, Rita, and Gary cannot be hers.
Mrs. White has a daughter, so you can count out the boys.
Mrs. Brown also have a daughter, so again you can count out the boys.
We know that Rita and Gary are not related, so they cannot be Gray.
Gary Green is 7 (He is not a Gray, White, or Brown so he has to be Green and he is elder than Larry and Tina)
Larry Gray is 4 (is younger than Tina and not Green, Brown or White, so he has to be a Gray)
Lisa White is 3 (is younger than the Brown girl)
Rita Brown is 5 (cannot be Gray or White as her mom is sometimes home on Saturdays)
Tina Gray is 6 (Older than Larry and younger than the Green child.)
there is a specific type of graph close to thing that can be used to numeral it out. i will see if i can find one online and send it to you
Here try this
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