# Word Problem?

Teri begins walking east at 2 miles per hour at 1 p.m.. If Cindy leaves from alike point 30 minutes later walking east at 3 miles per hour, when will she take in for questioning Teri?

Answers:    The other answers are not bad, but I estimate you want to know what time it will be when Cindy catches Teri.

Teri's RATE = 2 mph
Cindy's RATE = 3 mph

Let:
Teri's walking TIME = X

Then:
Cindy's walking TIME = X - 0.5

Cindy will corner Teri when the DISTANCE they have both walk is equal. The formula for distance is RATE multiplied by TIME.

Teri's DISTANCE = 2X
Cindy's DISTANCE = 3(X-0.5)

Therefore, Cindy will catch Teri when:

3(X-.05) = 2X
3X - 1.5 = 2X
X - 1.5 = 0
X = 1.5 (equals TIME Teri walks)

Teri will saunter 1.5 hours when Cindy catches her. Since Teri started at 1:00 p.m., Cindy will lock in her at 2:30 p.m.
Since 30 minutes is 0.5 hours, so Teri had an positive aspect of 0.5 hours.
n/2(2(0.5)+(n-1)(2))=n/2(2(0)+(n-1)(3)...
Cancel the n/2 from both sides:-
1+2n-2=3n-3
n=1
Therefore, Cindy will catch up near Teri one hour later.
You obligation to find out when the two will meet up.
Let "x" be the amount of time it take for the two walkers to assemble up.

2x = 3(x-0.5)
2x = 3x - 1.5
x = 1.5 hours
(2:30pm)

You have to subtract the 0.5 from the 'x' because Cindy gone 1/2 hour after Teri (so she had 1/2 hour smaller number time to walk).

To check, find out how far each personality will have walk by 2:30. The distances should be equal if they met each other.

Teri - At 2:30, she's walk for 1.5 hours
2(1.5) = 3 miles
Cindy - At 2:30, she's walked for 1hr
3(1) = 3 miles

3 miles = 3 miles

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